Two balls P and Q are at opposite ends of the diameter of a frictionless horizontal circular groove. P is projected along the groove and at the end of T second, it strikes ball Q. Let difference in their final velocities be proportional to the initial velocity of ball P and coefficient of proportionally is e then second strike occurs at
Text Solution
Verified by ExpertsThe correct answer is:
A
Let u be the initial velocity of ball P, then u = 
and difference in final velocities, v' – v =
ev(given)
Time for second strike = 
= 
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